u^2-4u-244=0

Solution for u^2-4u-244=0 equation:

u^2-4u-244=0

a = 1; b = -4; c = -244;
Δ = b2-4ac
Δ = -42-4·1·(-244)
Δ = 992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{992}=\sqrt{16*62}=\sqrt{16}*\sqrt{62}=4\sqrt{62}$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{62}}{2*1}=\frac{4-4\sqrt{62}}{2}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{62}}{2*1}=\frac{4+4\sqrt{62}}{2}
$